Yes, I was thinking more in terms of mental operations than physical.
I think the following works, but it doesn't seem entirely transparent :-)

Given array A, and a vector of row indices v  (ie 1 <= v <= dim(A)[1]), the
slice of rows v is

A[ outer(v, dim(A)[1]*( 1:prod(dim(A)[-1])-1 ), '+') ]


Steve Lianoglou-6 wrote:
> 
> You actually don't have to convert A to a vector, you can use vector- 
> style indexing into a matrix:
> 

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