Duncan Murdoch wrote:
baptiste auguie wrote:
it's documented as "unexpected"

?diag
Note

Using diag(x) can have unexpected effects if x is a vector that could be of
length one. Use diag(x, nrow = length(x)) for consistent behaviour.


And the result follows from this part,

    else if (length(x) == 1L && nargs() == 1L) {
        n <- as.integer(x)
        x <- 1
    }

Looks like the man page is wrong: it says diag(0.9) should produce a 1x1 matrix, but as the code shows, it produces a 0x0 one.
I'll fix it.

Oops, this has already been fixed. I was looking at an old version of R on this laptop.

Duncan Murdoch
Duncan Murdoch
baptiste

2009/9/4 Markku Karhunen <markku.karhu...@helsinki.fi>

Hi,

Does anybody know, what is going on here?

 diag(sqrt(1))
[,1]
[1,]    1

diag(sqrt(0.3333))

<0 x 0 matrix>

sqrt(1)

[1] 1

sqrt(0.3333)

[1] 0.5773214

BR, Markku Karhunen
researcher
University of Helsinki

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and provide commented, minimal, self-contained, reproducible code.


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and provide commented, minimal, self-contained, reproducible code.

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