Subodh Assuming the data is ordered by date then you can define fin.years = (0:(10*12-1)) %/% 12
then use aggregate: aggregate(x, list(fin.years),sum) HTH Schalk Heunis On Thu, Sep 17, 2009 at 6:11 PM, Subodh Acharya <[email protected]> wrote: > Hi everyone,I have a data daily data (x) for 10 years starting from > 04-01-1995 to 03-31-2005. > I was able to get the yearly sum for the ten years using > aggregate(x, years, sum). > But this gave me the yearly sum for 1995 (Apr- Dec); 1996 (Jan-Dec) > ---------2005 (Jan-Mar). > But I want to get the aggregates for Apr-1995 to Mar 1996, Apr 1996- mar > 1997 and so on. > > your help will be higly appreciated. > Thanks in advance > > -- > Acharya, Subodh > > [[alternative HTML version deleted]] > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
