On Sep 29, 2009, at 1:43 PM, Carlos Hernandez wrote:
Dear All,
I´m using the following code:
all1<-gg2[[1]][[1]]; for(i in 1:48){ all1 <- rbind(all1,gg2[[i]]
[[1]]) }
Looks to me that you would be getting a duplicate copy of the first
matrix, but aside from that what problems are you experiencing that
make you want different approaches? You have shot your self in the
foot for using simple methods by creating a more complex than needed
list structure:
> gg3 <- list(matrix(1:4, 2), matrix(5:8,2))
> gg3
[[1]]
[,1] [,2]
[1,] 1 3
[2,] 2 4
[[2]]
[,1] [,2]
[1,] 5 7
[2,] 6 8
> gg3 <- list(list(matrix(1:4, 2)), list(matrix(5:8,2)))
> gg3
[[1]]
[[1]][[1]]
[,1] [,2]
[1,] 1 3
[2,] 2 4
[[2]]
[[2]][[1]]
[,1] [,2]
[1,] 5 7
[2,] 6 8
This does work, but it is not "intuitive:
> rbind2 <- function (x) Reduce("rbind", x)
> rbind2(lapply(gg3, "[[", 1))
[,1] [,2]
[1,] 1 3
[2,] 2 4
[3,] 5 7
[4,] 6 8
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
to create a new matrix that contains all the matrices in a list
called gg2.
gg2 is a list that looks like
gg2
[[1]]
[[1]][[1]]
<matrix one>
[[2]]
[[2]][[1]]
<matrix two>
.
.
.
[[48]]
[[48]][[1]]
<matrix 48>
Is there a faster way to do the rbind?
i've tried do.call("rbind",gg2) but does not work.
Thank you for any hints or advice!
Best regards,
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