On Nov 18, 2009, at 11:00 PM, ychu066 wrote:
hey Jim ,
I have solve the column name problems now. But i am still unable to
read
the date in R ...
toms_dat<- replace(toms_dat, toms_dat ==2009-08-24, 6)
replace needs its first argument to be a vector, while you have given
it a dataframe.
Look at these examples:
> toms <- data.frame(a=letters[1:10], b=Sys.Date() + 1:10)
> toms
a b
1 a 2009-11-20
2 b 2009-11-21
3 c 2009-11-22
4 d 2009-11-23
5 e 2009-11-24
6 f 2009-11-25
7 g 2009-11-26
8 h 2009-11-27
9 i 2009-11-28
10 j 2009-11-29
> replace(toms$b, toms$b=="2009-11-23", 6)
Error in as.Date.numeric(value) : 'origin' must be supplied
Notice that this did not
> replace(toms$b, toms$b=="2009-11-23", "2008-01-01")
[1] "2009-11-20" "2009-11-21" "2009-11-22" "2008-01-01" "2009-11-24"
"2009-11-25" "2009-11-26"
[8] "2009-11-27" "2009-11-28" "2009-11-29"
> toms
a b
1 a 2009-11-20
2 b 2009-11-21
3 c 2009-11-22
4 d 2009-11-23
5 e 2009-11-24
6 f 2009-11-25
7 g 2009-11-26
8 h 2009-11-27
9 i 2009-11-28
10 j 2009-11-29
Notice that the replace() operation did not do anything to "toms". If
you had wanted it to, you would have needed to do:
toms$b <- replace(toms$b, toms$b=="2009-11-23", "2008-01-01")
Now, if you want further assistance you need to provide a working
excaple that has the same features as your problem. Use str(toms_dat)
to see what type your columns are ant then perhaps:
dput(head(toms_dat))
or:
dump("toms_dat", file=stdout() )
or if toms_dat is big, then:
smalltoms <- head(toms_dat)
dump("smalltoms", stdout() )
the toms_dat is a data frame , and I want to replace the date to be a
single number eg:1,2,3, ....
regards,
Tom.
jholtman wrote:
First of all '2009-08-06' is 1995; this is probably not what you were
expecting. What do you what your expression to do? Is 'toms_dat' a
dataframe? if so, your expression 'toms_dat ==2009-08-06' seem
strange. So tell us what you want to do, not how you want to do it.
On Tue, Nov 17, 2009 at 4:54 PM, ychu066 <ychu...@aucklanduni.ac.nz>
wrote:
hi everyone, i am having difficulties with replacing the dates
format in
R
for exporting the data set...
eg: the code that i used was
toms_dat<- replace(toms_dat, toms_dat ==2009-08-06, 2)
toms_dat<- replace(toms_dat, toms_dat ==2009-08-04, 1)
but when i export the data as into txt file or excel file the
dates come
up
with very large numbers .....:drunk:
please help me ...=)
--
View this message in context:
http://old.nabble.com/replacing-the-dates-format-in-R-for-exporting-the-data-set...-tp26396492p26396492.html
Sent from the R help mailing list archive at Nabble.com.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
View this message in context:
http://old.nabble.com/replacing-the-dates-format-in-R-for-exporting-the-data-set...-tp26396492p26420068.html
Sent from the R help mailing list archive at Nabble.com.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
