Does the survey package have a function similar to prop.test() Or is there a way to use svyciprop() to perform a Chi-square test to see if the difference in proportions is significant?
I'm comparing liberal congregations with conservative congregations in their sponsorship of HIV/AIDS programs. I want to test whether the proportion of liberal congregations sponsoring a program is significantly different from the proportion of conservative congregations sponsoring a program. Thanks Brad Thomas Lumley wrote: > > > Version 3.18 of the survey package is now percolating through CRAN. > > Since the last announcement on this list, in February, the main additions > are > - svyciprop() for confidence intervals on proportions, especially in > small samples or near 0 or 1. > -thomas > > Thomas Lumley Assoc. Professor, Biostatistics > tlum...@u.washington.edu University of Washington, Seattle > > _______________________________________________ > R-packages mailing list > r-packa...@r-project.org > https://stat.ethz.ch/mailman/listinfo/r-packages > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > -- View this message in context: http://n4.nabble.com/R-pkgs-survey-package-3-18-tp904297p957421.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.