Dear Sir,
Thanks a lot for your quick solution. But still I will like someone to guide me
the solution as per my requirement. The problem is actually I am not looking
for the square of each term. I have used it to give some example since I didn't
want to confuse the matter. My process is altogether different and I need to
use loop. So here is my actual code. I am trying to use Historical simulation
and for that I need to calculate LN(New rate / old rate for each of the
instrument separately).
Here is my actual code -
ONS = read.csv('Instrument.csv')
n = length(ONS)
Y = NULL
B = array()
for (i in 1 : n)
{
Y[i] = ONS[i]
j <- 1
for (j in 1:(length(Y[[i]])-1))
{
B[j] <- log((Y[[i]][j+1])/(Y[[i]][j]))
j <- j+1
}
}
--- On Mon, 15/2/10, Benilton Carvalho <beniltoncarva...@gmail.com> wrote:
From: Benilton Carvalho <beniltoncarva...@gmail.com>
Subject: Re: [R] CORRECTION - Storing results in a loop
To: "Madhavi Bhave" <madhavi_bh...@yahoo.com>
Cc: r-help@r-project.org
Date: Monday, 15 February, 2010, 4:29 AM
sorry, meant to type:
B = ONS^2
cheers,
benilton
On Mon, Feb 15, 2010 at 12:28 PM, Benilton Carvalho
<beniltoncarva...@gmail.com> wrote:
> maybe you just want
>
> Y = ONS^2
>
> ?
>
> b
>
> On Mon, Feb 15, 2010 at 12:22 PM, Madhavi Bhave <madhavi_bh...@yahoo.com>
> wrote:
>> Dear R Helpers
>>
>> (There is a small correction in my earlier mail. In the 'instrument.csv'
>> file, I had mentioned only three columns. Actually there are 7 columns. I
>> regret the error. Rest contents remains the same. Thanks)
>>
>> I have an 'instrument.csv' file with 7 instrument names and 5 rates each
>> i.e. it has 7 columns and 6 rows (including row names).
>>
>> 'instrument.csv'
>>
>> instrument1 instrument2 ........ instrument7
>> 12 5 14
>> 11 7 7
>> 14 11 3
>> 8 21 10
>> 11 3 5
>>
>>
>> Following is my R code.
>>
>> ONS = read.csv('Instrument.csv')
>> n = length(ONS)
>>
>> Y = NULL
>> B = NULL
>>
>> for (i in 1 : n)
>>
>> {
>>
>> Y[i] = ONS[i]
>>
>> for (j in 1 : length(Y[[i]]))
>> {
>> B[j] = (Y[[i]][j])^2
>> }
>>
>> }
>>
>> Problem is when I type B, I get the processed result only for the last
>> column i.e. Y[7]. It doesn't store results for Y[1] to Y[7].
>>
>> I need B[1], B[2].......upto B[7].
>>
>> Please guide me how do I store individual column processed results?
>>
>> Thanking you all in advance
>>
>> Regards
>>
>> Madhavi
>>
>>
>>
>>
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>>
>>
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>>
>>
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