I have split my original dataframe to generate a list of dataframes each of which has 3 columns of factors and a 4th column of numeric data. I would like to use lapply to apply the fitdistr() function to only the 4th column (x$isi) of the dataframes in the list.
Is there a way to do this or am I misusing lapply? As a second solution I tried splitting only the numeric data column to yield a list of vectors and then using lapply(myList, fitdistr, densfun='gamma',start=list(scale=1, shape=2)) returns the error: Error in optim(x = c(305, 290, 283, 363, 331, 293, 304, 312, 286, 339, : non-finite finite-difference value [2] In addition: Warning message: In dgamma(x, shape, scale, log) : NaNs produced However, if I use fitdistr(myList[[i]]) on each element of the list, there are no errors. Thanks in advance for any comments. -jason -- View this message in context: http://n4.nabble.com/lapply-and-list-indexing-basics-after-realizing-I-wasn-t-previously-subscribed-sorry-tp1584053p1584053.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
