On Apr 1, 2010, at 8:19 AM, Silvano wrote:

Hi,

I have a dichotomous variable (Q1) whose answers are Yes or No.
Also I have 2 categorical explanatory variables (V1 and V2) with two levels each.

I used logistic regression to determine whether there is an effect of V1, V2 or an interaction between them.

I used the R and SAS, just for the conference. It happens that there is disagreement about the effect of the explanatory variables between the two softwares.

Not really. You are incorrectly interpreting what SAS is reporting to you, although in your defense I think it is SAS's fault, and that what SA is reproting is nonsensical.


R:
q1 = glm(Q1~grau*genero, family=binomial, data=dados)
anova(q1, test="Chisq")

          Df Deviance Resid. Df Resid. Dev P(>|Chi|)
NULL                          202     277.82
grau         1   4.3537       201     273.46   0.03693 *
genero       1   1.4775       200     271.99   0.22417
grau:genero  1   0.0001       199     271.99   0.99031

SAS:
proc logistic data=psico;
class genero (param=ref ref='0') grau (param=ref ref='0');
model Q1 = grau genero grau*genero / expb;
run;
                                 Type 3 Analysis of Effects
                                                    Wald
                       Effect           DF    Chi-Square Pr > ChiSq

                       grau              1        1.6835 0.1945
                       genero            1        0.7789 0.3775
                       genero*grau       1        0.0002 0.9902

I'm having difficulty figuring our how "type 3" analysis makes any sense in this situation. Remember that "type 3" analysis supposedly gives you an estimate for a covariate that is independent of its order of entry. How could you sensible be adding either of those "main effects" terms to a model that already had the interaction and the other covariate in it already? The nested model perspective offered by R seems much more sensible.

--
David



The parameters estimates are the same for both.
Coefficients:
           Estimate Std. Error z value Pr(>|z|)
(Intercept)  0.191055   0.310016   0.616    0.538
grau         0.562717   0.433615   1.298    0.194
genero      -0.355358   0.402650  -0.883    0.377
grau:genero  0.007052   0.580837   0.012    0.990

What am I doing wrong?

Thanks,

--------------------------------------
Silvano Cesar da Costa
Departamento de Estatística
Universidade Estadual de Londrina
Fone: 3371-4346

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to