Wow, those are much more elegant. Thanks! Peter suggests:
df[] <- lapply(df, factor, levels=allLevels, labels=seq_along(allLevels)) Henrique suggests: df[] <- as.numeric(unlist(df)) In both of those cases, why is the [] needed? When I evaluate df vs. df[], they both look the same, but apparently they have different meanings. Is a data frame internally represented as a list, and does df[] let you assign to the elements of the list while maintaining the object's nature as a data frame? Moreover, Henrique, why is it that what you suggested works if done in one line, but not in two? That is, df[] <- unlist(df) df[] <- as.numeric(df[]) gives an error at the second line: "Error: (list) object cannot be coerced to type 'double'." -- View this message in context: http://n4.nabble.com/Sharing-levels-across-multiple-factor-vectors-tp1747714p1748436.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
