Dear list, Is it possible to replace the median in the following code so as to calculate 5 and 95% tiles?
with( raunheim, aggregate(no, by = list(wd,hr), FUN = "median", na.rm=TRUE) ) Regards, Philip Sinclair ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
