Uwe Ligges <[EMAIL PROTECTED]> writes: > nn.Exp <- substitute(a$b, list(b=nn[1])) > eval(nn.Exp)
Thanks, Uwe. It does work, but, surely using brackets is better. -Serge ______________________________________________ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
