Hello Andy
thanks for this; but
R> x <- 1:10
R> f
function(n) {
if(is.null(n) || is.na(n) || abs(n) < pi) {
return(FALSE)
} else {
return(TRUE)
}
}
R> x <- 1:10
R> f(x[x>11])
Error in if (is.null(n) || is.na(n) || abs(n) < pi) { :
missing value where logical needed
>
>
> Try:
>
> f <- function(n) {
> if(is.null(n) || is.na(n) || abs(n) < pi) {
> return(FALSE)
> } else {
> return(TRUE)
> }
> }
>
> Note that the order of the conditions inside if() matters: is.na(n) only
> gets evaluated if is.null(n) is FALSE, and so on.
>
> Andy
>
--
Robin Hankin, Lecturer,
School of Geography and Environmental Science
Tamaki Campus
Private Bag 92019 Auckland
New Zealand
[EMAIL PROTECTED]
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