It is not clear to me that one can. If the singular value decomposition of A is the triple product P d Q', then the singular value decomposition of A'A=S is Q d^2 Q'. The information about the orthonormal matrix P is lost, is it not? ********************************************************** Cliff Lunneborg, Professor Emeritus, Statistics & Psychology, University of Washington, Seattle Visiting: Melbourne, Feb-May 1999, Brisbane, Jun-Aug 1999, Sydney, Sep-Nov 1999, Perth, Dec 1999-Feb 2000 [EMAIL PROTECTED]
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