Your sequence is 1:a + k*(a+b) where a=8, b=5 and k=0,1,...,K. You can make use of the fact that R loops of vectors if two vectors are not the same;
a <- 8 b <- 5 K <- 49 x <- rep((0:K)*(a+b), each=a) + 1:a Cheers Henrik Bengtsson > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of Jeremy Z Butler > Sent: den 4 mars 2003 14:14 > To: [EMAIL PROTECTED] > Subject: [R] for loop problem > > > Hi, > I'm just coming to grips with "for" looping etc. and have a bit of a > problem: > > I want to generate a sequence which goes > 1 2 3 4 5 6 7 8 14 15 16 17 18 19 20 21 26 27 ... > i.e. 8 consecutive numbers then 5 missed then the next 8 > numbers etc. I was going to do this using the seq() function > but couldn't figure out how > so I thought I'd try a loop: > > for (x in seq(1,650,13)) > { num.set.1 <- x:x+8 > } > but now what I need to do is write code such that each time > it goes through > the loop it assigns the output to a different object e.g. > num.set.1 on the > first loop then num.set.2 on the next etc. so that they can > be concatenated. > Is there any way to do this?? > > I may be doing this an extremely complicated way but with my zero > programming experience its the best I can think of. Can anyone help? > > J > > ______________________________________________ > [EMAIL PROTECTED] mailing list > http://www.stat.math.ethz.ch/mailman/listinfo/> r-help > > ______________________________________________ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
