let's compare lda and discrimin (ade4) using the iris data:
with lda I get: > lda1 <- lda(iris[,1:4],iris[,5]) > lda1$svd [1] 48.642644 4.579983 with discrimin: > discrimin1 <- discrimin(dudi.pca(iris[,1:4],scan=F),iris[,5],scan=F) > discrimin1 eigen values: 0.9699 0.222 so where and how is the relationship? thanks christoph On Tue, 2003-06-03 at 13:01, Prof Brian Ripley wrote: > On Tue, 3 Jun 2003, Stephane Dray wrote: > > > >On Tue, 3 Jun 2003, Christoph Lehmann wrote: > > > > > >> How can I get the eigenvalues out of an lda analysis? > > > > > >It uses singular values not eigenvalues: see ?lda for a description of the > > >output, and the print method for one way to use them. > > > > the function discrimin ofthe ade4 package performs discriminat > > analysis with eigen and so produces eigenvalues ($eig) > > For those for whom squaring is too difficult, that is. > Why recommend software using an inferior algorithm to avoid squaring? -- Christoph Lehmann <[EMAIL PROTECTED]> ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
