This works in R 1.7.1: please upgrade. [That's assuming that your sequence actually covers the data: you need to go beyond max(cas.param) to be sure, and it looks to me that with right=FALSE and include.lowest-FALSE the breaks never will cover the data.]
On Tue, 17 Jun 2003, Petr Pikal wrote: > Dear all > > I would like to aggregate a data frame in a three minute interval. I have a time > vector: > > > str(cas.param) > `POSIXct', format: chr [1:181] "2003-06-12 09:00:00" "2003-06-12 09:01:00" > "2003-06-12 09:02:00" > > and I want to turn it into a factor by cut. It works if I want to break it in let > say > hours > > > str(cut(cas.param,breaks="hour")) > Factor w/ 3 levels "2003-06-12 ..",..: 1 1 1 1 1 1 1 1 1 1 . > > But if i tried to do similar task but to construct three minutes intervals with a > vector of cut points it gives me an error > > > cut(cas.param,breaks=seq(min(cas.param),max(cas.param), by="3 mins")) > Error in sort(breaks) : `x' must be atomic > > however > > > str(seq(min(cas.param),max(cas.param), by="3 mins")) > `POSIXct', format: chr [1:61] "2003-06-12 09:00:00" "2003-06-12 09:03:00" > "2003-06-12 09:06:00" > > works. > > So it is definitely my lack of understanding how to implement a vector of cut > points (constructed by seq()), to break parameter of cut() function. > > Please can you give me any hints? > > R 1.7.0, Windows NT > > Thanks a lot > > Petr Pikal > [EMAIL PROTECTED] > [EMAIL PROTECTED] > > ______________________________________________ > [EMAIL PROTECTED] mailing list > https://www.stat.math.ethz.ch/mailman/listinfo/r-help > -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
