Thomas Lumley <[EMAIL PROTECTED]> writes:
> On Wed, 30 Jul 2003, Damon Wischik wrote:
>
> >
> > Why does
> > > curve(function(y) y^2, from=0,to=1)
> > not work, whereas
> > > myf <- function(y) y^2
> > > curve(myf, from=0,to=1)
> > work?
> >
>
> Because someone was trying to be too clever in writing curve(). The first
> argument must either be an expression with the free variable `x' or the
> *name* of a function. You can't specify a literal function or the name of
> an expression.
>
> The reason is that it is hard to tell whether an argument is a function or
> an expression without evaluating it, and if it's an expression you may not
> be able to evaluate it.
>
> You could always use
> plot(function(y) y^2)
Actually, it wouldn't be too hard to use identical(sexpr[[1]],
as.name("function")) and detect an explicit function definition, so
someone could have been even more clever...
--
O__ ---- Peter Dalgaard Blegdamsvej 3
c/ /'_ --- Dept. of Biostatistics 2200 Cph. N
(*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918
~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907
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