The first model includes C and interactions with C, which are combined with the residuals in the other two models. The first model has 3, 3, 3, 3, and 32 degrees of freedom for C, A:C, B:C, A:B:C, and residuals, respectively. The other two models combine these two into a single residual term with 44 = 3 + 3 + 3 + 3 + 32 degrees of freedom.

hope this helps. spencer graves

Cec�lia Shiraiwa wrote:

   Hello all,
   I�m trying to study a factorial design, but I can�t understand why did Df, Sum Sq 
and Mean Sq of residuals alter when I Split the interaction? I think that Split the 
interaction must not alter the residuals. Am I doing something wrong?
   Could anyone help me?
   My data and functions I tried are:

Y<-c(196,213,183,
       192,253,199,
       251,331,276,
       128,220,196,
       272,275,227,
       204,305,185,
       135,322,276,
       262,284,250,
       272,275,227,
       204,305,185,
       135,322,276,
       262,284,250,
       296,369,344,
       325,396,403,
       370,323,319,
       341,418,318)
A<-factor(rep(c(0,1),c(24,24)))
B<-factor(rep(c(0,1,0,1),c(12,12,12,12)))
C<-factor(rep(c(rep(0:3,each=3)),times=4))
av <- aov(Y ~ A + B + A*B + C + A*C + B*C + A*B*C )
summary(av)
avAB <- aov(Y ~ A/B)
summary (avAB, split=list("A:B"=list(A1=1, A2=2)))
avBA <- aov(Y ~ B/A)
summary (avBA, split=list("B:A"=list(B1=1, B2=2)))


Thanks Cecilia

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