> apply(ib5km.lincol.random[1:3,], 1, function(i) ib5km15.dbc[i[1],i[2],])
(untested)
-- Tony Plate
At Wednesday 06:47 PM 10/15/2003 +0200, Agustin Lobo wrote:
Hi!
I have a 3d array: > dim(ib5km15.dbc) [1] 190 241 19
and a set of positions to extract: > ib5km.lincol.random[1:3,] [,1] [,2] [1,] 78 70 [2,] 29 213 [3,] 180 22
Geting the values of a 2D array for that set of positions would be:
> ima <- ib5km15.dbc[,,1] > ima[ib5km.lincol.random[1:10,]]
but don't find the way for the case of the 3D array:
> ib5km15.dbc[ib5km.lincol.random[1:10,],] Error in ib5km15.dbc[ib5km.lincol.random[1:10, ], ] : incorrect number of dimensions
Could anyone suggest the way of subseting the 3D array to get a vector of z values for each position recorded in ib5km.lincol.random? (avoiding the use of for loops).
Thanks
Agus
Dr. Agustin Lobo Instituto de Ciencias de la Tierra (CSIC) Lluis Sole Sabaris s/n 08028 Barcelona SPAIN tel 34 93409 5410 fax 34 93411 0012 [EMAIL PROTECTED]
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