On Thu, 16 Oct 2003, Robin Hankin wrote:
>
> what I want is the equivalent of
>
> R> rbind(a[[1]],a[[2]],a[[3]],a[[4]],a[[5]])
>
Note that while do.call("rbind",a) is the natural solution it may in fact
be faster to create a matrix and use a loop to put things in it.
rval<-matrix(ncol=4, nrow=sum(sapply(a,nrow)))
i<-1
for(ai in a){
r<-nrow(ai)
rval[i+1:r,]<-ai
i<- i+r
}
-thomas
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