How does that compare with the following:
for (myname in names(myframe)[1:4]){
mdl <- formula(paste(myname, "~ etc.etc"))
myfit <- lm(mdl, data=myframe)
print(summary(myfit))
}Or:
for (myname in names(myframe)[1:4]){
lm.txt <- paste("lm(", myname, "~ etc.etc, data=myframe)")
myfit <- eval(parse(text=lm.txt))
print(summary(myfit))
}You are teaching me new uses of "substitute", and I just wonder about the relative advantages and disadvantages of the different approaches.
Thanks,
spencer gravesPeter Dalgaard wrote:
"Subramanian Karthikeyan" <[EMAIL PROTECTED]> writes:
My previous question put in a simpler way:
How would I pass a value of a variable to a function such as
lm(Effect1~Trt*Dose, data = x, contrasts = list(Trt = contr.sum, Dose = contr.sum))?
Here, 'Effect' is a column name in my data matrix, and I want "Effect1" to
be replaced by "Effect2" and so on (my other column names in the data
frame) for successive anova calculations. So I am storing the column names
as an array, and passing the array as a parameter to the lm() function.
A canonical trick is
for (myname in names(myframe)){ mycall <- substitute(lm(myvar~etc.etc.....),list(myvar=as.name(myname))) myfit <- eval(mycall) print(summary(myfit)) }
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