Hi all, thank you for replying so quickly! I have another problem:
step.wise <- stepwise(data.table[,names(good.motifs[,1])], data.table[1], f.crit=fval.cutoff) s-plus has the stepwise() formula but R has step() and stepAIC() from base and MASS packages. I cannot seem to figure out how to convert the above stepwise to either step() or stepAIC(). > data.table[,names(good.motifs[,1])] SO0404 -9.861773e-02 -3.280285e-02 -1.005750e-01 -7.363912e-02 -5.880977e-02 SO0403 3.962532e-02 9.791646e-03 2.854144e-03 3.393920e-02 5.433459e-02 SO0314 4.286539e-02 4.075057e-02 1.594184e-02 2.591711e-02 -6.343293e-04 SO4348 4.027333e-02 3.888057e-02 2.521229e-02 -4.118126e-04 -3.077392e-03 SO3919 1.219271e-02 -2.675035e-03 5.320541e-02 -4.118126e-04 2.410169e-02 > data.table[1] SO0404 -0.11244436 SO0403 -0.11963379 SO0314 -0.13039490 SO4348 -0.14484288 SO3919 -0.14548809 Can anyone help? Best regards, Ognen On Fri, 5 Dec 2003, Tony Plate wrote: > Date: Fri, 05 Dec 2003 09:57:56 -0700 > From: Tony Plate <[EMAIL PROTECTED]> > To: Ognen Duzlevski <[EMAIL PROTECTED]>, [EMAIL PROTECTED] > Subject: Re: [R] s-plus to R > > I'd suggest just removing the "+" and see if that works. It's somewhat > difficult to say whether that would be safe without seeing more of your > code, but "+" as a unary operator on character vectors seems to be an > identity function in S-plus 6.1, e.g.: > > > print(+ letters[1:3]) > [1] "a" "b" "c" > > deparse(+ letters[1:3]) > [1] "c(\"a\", \"b\", \"c\")" > > > > Maybe it has some side effects in S-plus (like invisible()?), but if the > code depends on these you will probably have to code these in a different > way in R anyway. I don't know -- I haven't before seen "+" used as a unary > operator on character vectors. > > hope this helps, > > Tony Plate > > > At Friday 04:33 PM 12/5/2003 +0000, Ognen Duzlevski wrote: > >Hi, I have a piece of code originally written for s-plus - I am trying to > >run it in R now. The code was obtained from someone who is now not > >available to give any pointers and I am a beginner in R. Here is where it > >is getting stuck: > > > > > +names(good.motifs[,1]) > >Error in +names(good.motifs[, 1]) : Invalid argument to unary operator > > > >here is now names(good.motifs,1]) looks: > > > names(good.motifs[,1]) > >[1] "Motif.P1.8.3" "Motif.P1.9.14" "Motif.P1.10.1" "Motif.P1.11.8" > >[5] "Motif.P1.15.1" > > > >Can anyone help with an equivalent in R? > > > >Thanks, > >Ognen > > > >______________________________________________ > >[EMAIL PROTECTED] mailing list > >https://www.stat.math.ethz.ch/mailman/listinfo/r-help > > Tony Plate [EMAIL PROTECTED] > > [EMAIL PROTECTED] SDF Public Access UNIX System - http://sdf.lonestar.org ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
