Jonathan Baron <[EMAIL PROTECTED]> writes: > On 01/19/04 19:27, Laura Quinn wrote: > >I am trying to perform the following calculation for a very > >large time series data set: > > > >x<-unit(length*data.frame.a*data.frame.b,"cm") > > > >data.frame.a and data.frame.b are of the same dimension, and I wish to > >perform the calculation in one step so that "x" is returned as a > >matrix/data.frame of equal dimension. > > Sounds like mapply() would be useful. It works on columns of > data frames. The default is "simplify=TRUE" so it will try to > return a vector or matrix.
Maybe, but what was ever wrong with length*as.matrix(data.frame.a)*as.matrix(data.frame.b) or, possibly, as.data.frame thereof? -- O__ ---- Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907 ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
