I could not find any information on how `read.spss' deals with date information. As an example, I created a file containing two variables, one numeric (values = (1, 2)) and one of type "Datum" in SPSS (german version with values "11.02.2003" and "03.04.1999" and I get in R:
SPSSfile = url("http://www.imbe.med.uni-erlangen.de/~hothorn/dates.sav";, "rb") SPSSdata = readBin(SPSSfile, "numeric", n = 10000) writeBin(SPSSdata, con = "dummy.sav") library(foreign) read.spss("dummy.sav")
$DUMMY [1] 1 2
$DATE [1] 13264300800 13142476800
attr(,"label.table") attr(,"label.table")$DUMMY NULL
attr(,"label.table")$DATE NULL
Could anyone give me a a hint how I can convert 13264300800 to 2003/02/11 again, please?
Date variables in SPSS contain the number of seconds since October 14, 1582. I think you could do something like this to convert:
> ISOdate(1582, 10, 14) + c(13264300800, 13142476800) [1] "2003-02-11 07:00:00 Eastern Standard Time" [2] "1999-04-03 07:00:00 Eastern Standard Time"
hope this helps,
Chuck Cleland
-- Chuck Cleland, Ph.D. NDRI, Inc. 71 West 23rd Street, 8th floor New York, NY 10010 tel: (212) 845-4495 (Tu, Th) tel: (732) 452-1424 (M, W, F) fax: (917) 438-0894
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