You assigned `f' whatever the result of
sub("(.+/.+?/)(.+)?","\\2",p,perl=TRUE) is. The only way for `f' not to
exist after that assignment (that I can think of anyway) is if there was an
error raised in the sub() call. Otherwise `f' will always exist! You
should simply check what value `f' has. My guess is that you really want
something like:
if (f == "") ...
or maybe:
if (nchar(f) == 0) ...
Andy
> From: Fred J.
>
> Hello
> I am trying for an hour now,
>
> > p <- "c:/data/"
> or
> > p <- "c:/data/abc.hig"
>
> d <- sub("(.+/.+?/)(.+)","\\1",p,perl=TRUE)
> f <- sub("(.+/.+?/)(.+)?","\\2",p,perl=TRUE)
>
> if (exists("f")){ #why this gives TRUE no mater what?
> do this with d and f
> } else {
> do that with d
> }
>
>
> thanks
>
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