On Mon, 5 Apr 2004, S�ren H�jsgaard wrote: > Suppose I have > f1 <- function(x) x > f2 <- function(x) x^2 > funlist <- list(f1,f2) > Then I would like to evaluate funlist such that when x is 10 I should get a list > with 10 and 100. > > A naive way of doint this is > myf <- funlist[[1]] > do.call(paste(quote(myf)), list(x=10)) > myf <- funlist[[2]] > do.call(paste(quote(myf)), list(x=10))
> - but there has to be much more elegant ways of doing this. I just can't > figure out how.. lapply(funlist, function(f, x)f(x), x=10) > Put more generally, is there a way of making R "understand" > automatically that funlist above is really a function of x? It isn't. It is a list of functions of , so use lapply. > A related question is that of anonymous functions: how to evaluate > function(x)x^2 on x<-10 without assigning the function to a name? > (function(x)x^2)(10) [1] 100 -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
