rank((-x$a)) rank() does not work on lists but on numeric vectors, and the above works generally for numeric vectors.
On Tue, 20 Apr 2004, Manoj - Hachibushu Capital wrote: > Dear All, > Is there any simple way to way to produce "rank", for a given > list, but in a descending order? > > E.G: > x = list(a=c(1,5,2,4)); > rank(x$a); produces 1,4,2,3 > > However I am looking for a way to generate (4,1,3,2). > > It would be particularly nice if the proposed solution has all > the niceties of rank function (like NA handling and ties.method > functionality) -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
