predict(lm(AV~as.factor(GROUP)))
Felix Eschenburg <Atropin75 <at> t-online.de> writes: : : Hello list ! : : I have a huge data.frame with several variables observed on about 3000 : persons. For every person (row) there is variable called GROUP which indices : the group the person belongs to. There is also another variable AV for each : person. Now i want to create a new variable which holds the group mean of AV : as a value for each person. : With tapply(AV,GROUP,mean) i get the means for each level of GROUP, but i : cannot find out, how to give every person the groupmean as a value (every : person should have the same value as every other person in the same group). : : Has anybody any ideas how to do that ? : : Yours sincerly : Felix Eschenburg ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
