Hoeven, Maarten van der <Maarten.van.der.Hoeven <at> knmi.nl> writes:
: suppose I have a date, say May 15 2004, and I want to now what date it is 23
days before that date. The way to
: calculate the new date should (...) take account of leap years :)
:
: In pseudocode:
:
: olddate <- "May 15 2004"
: newdate <- olddate-23
:
: I looked around in POSIXct etc..., maybe I overlooked?
as.Date("2005-05-24")-23
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