On 28-May-04 Ted Harding wrote: > > (1:100)[sort(runif(100),index.return=TRUE)] > > 37 99 22 66 12 36 90 48 55 45 98 59 92 20 46 23 2 74 > 80 5 63 27 56 60 51 76 39 87 19 96 29 15 18 100 52 3 > 70 8 67 42 43 57 91 21 25 78 41 1 34 68 77 9 72 73 > 11 89 83 94 65 13 14 81 24 58 35 44 10 79 50 49 6 28 > 17 33 4 71 82 31 75 30 85 93 26 69 38 84 32 54 64 53 > 88 61 86 97 7 62 95 47 16 40 > > but there may be a slicker way ... > Ted.
Of course there is (if what you want in random order is (1:100)) since that's what sort(runif(100),index.return=TRUE)$ix gives you anyway, and the initial (1;100) is redundant! However, if it's some other set X of 100 items that you want in random order then X[sort(runif(100),index.return=TRUE)$ix] is indeed what you need. Ted. -------------------------------------------------------------------- E-Mail: (Ted Harding) <[EMAIL PROTECTED]> Fax-to-email: +44 (0)870 167 1972 Date: 28-May-04 Time: 17:57:56 ------------------------------ XFMail ------------------------------ ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
