>>>>> "Eryk" == Eryk Wolski <[EMAIL PROTECTED]>
>>>>> on Tue, 01 Jun 2004 20:03:03 +0200 writes:
Eryk> Hi! U can use.
Eryk> rbind(t1,t2,t3)
yes, but not for getting a data frame!
nor does give
as.data.frame( rbind(t1,t2,t3) )
give the correct result {make use of str(.) to see this quickly}
Correct (though not "extremely simple") is
do.call("rbind", lapply(list(t1,t2,t3), as.data.frame))
> str(do.call("rbind", lapply(list(t1,t2,t3), as.data.frame)))
`data.frame': 3 obs. of 5 variables:
$ fname : Factor w/ 2 levels "animal1","animal2": 1 1 2
$ testname: Factor w/ 2 levels "hyla","bufo": 1 2 1
$ dspkr : Factor w/ 2 levels "left","right": 1 1 2
$ res1 : num 39.7 14.4 22.6
$ res2 : num 15 56.1 11.8
Eryk> On 6/1/2004 at 10:55 AM Randy Zelick wrote:
>> Hi there,
>>
>> I have some data which are convenient to enter as
>> lists. For example:
>>
>> t1<-list(fname="animal1",testname="hyla",dspkr="left",res1=39.7,res2=15.0)
>> t2<-list(fname="animal1",testname="bufo",dspkr="left",res1=14.4,res2=56.1)
>> t3<-list(fname="animal2",testname="hyla",dspkr="right",res1=22.6,res2=11.8)
>>
>> I would like to generate a dataframe, but *not* the way
>> this approach works...
>>
>> fdf<-data.frame(t1,t2,t3)
>>
>> fdf
>>
>> fname testname dspkr res1 res2 fname testname dspkr res1
>> res2 ... 1 animal1 hyla left 39.7 15 animal1 bufo left
>> 14.4 56.1 ...
>>
>>
>> Instead, what I would like is:
>>
>> fname testname dspkr res1 res2
>>
>> t1 animal1 hyla left 39.7 15.0 t2 animal1 bufo left 14.4
>> 56.1 t3 animal2 hyla right 22.6 11.8
>>
>>
>> or this would be fine too...
>>
>> x fname testname dspkr res1 res2
>>
>> 1 t1 animal1 hyla left 39.7 15.0 2 t2 animal1 bufo left
>> 14.4 56.1 3 t3 animal2 hyla right 22.6 11.8
>>
>> Is there a practical (hopefully simple) way to do this?
>>
>> Thanks,
>>
>> =Randy=
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