Ko-Kang Kevin Wang wrote:
[Forwarding on behalf of a colleague]
She's got a list with several tables:
tab <- list() for(i in 1:6) {
Most easy solution:
Make freq[i] a factor with all the levels that may appear. Then all tables have same dimension, e.g.:
tab <- lapply(freq, function(x) table(
factor(x, levels = c(0, 0.17, 0.3, 0.5, 1, 2.5, 3, 4))))Simplify yourself - I don't know much about "freq" ...
Uwe
+ tab[[i]] <- table(freq[i]) + }
tab
[[1]]
0 0.17 0.3 0.5 1 2.5 3 4 196 2 5 1 5 2 5 2
[[2]]
0 0.17 0.3 1 2.5 3 4 199 1 3 6 2 6 1
[[3]]
0 0.5 217 1
[[4]]
0 2.5 216 2
[[5]]
0 0.17 0.3 0.5 1 2.5 3 4 207 1 1 1 1 2 4 1
[[6]]
0 0.17 3 216 1 1
And would like to convert to a data frame, like:
0 0.17 0.3 0.5 1 196 2 5 1 5 199 1 3 0 6 217 0 0 1 0 [snip]
Basically down the columns she'd like to have the counts. But because each table in the list has got different number of columns, I've been unable to convert them into a data frame for her.
Any help would be greatly appreciated!
Cheers,
Kevin
______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
