I don't see why this needs to be iterative: the computations could be done
in parallel. But via a for loop you could use
for(i in 1:122) {
nm <- paste("L", i, sep="")
assign(nm, log(get(nm))
}
You would do better, I think, to have 122 similar data items in a list.
datalist <- lapply(1:122, function(x) get(paste("L", x, sep="")))
Then you could just do
logdatalist <- lapply(datalist, log)
and so on.
On Tue, 15 Jun 2004, Jin Shusong wrote:
> I have 122 vectors named from L1 to L122. Now I hope to
> take log to each of the series, say
> L1 <- log(L1)
> ...
> L122<-log(L122)
>
> Can anyone show me a iterative way to make the job simple.
> I mean the way something like
> for(i in 1:122){
> ...
> }
> or other similar methods.
--
Brian D. Ripley, [EMAIL PROTECTED]
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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