On 15-Jun-04 Peter Dalgaard wrote: > (Ted Harding) <[EMAIL PROTECTED]> writes: > > ... >> then I'd like to end up with a single factor with levels >> >> A0B0, A0B1, A0B2, A1B0, A1B1, A1B2 >> >> according to all the combinations which actually occur in the >> data (e.g. if (A1,B2) did not occur in the data, then A1B2 would >> not be a level in the resulting "glued" factor). >> >> I can see clumsy and tedious ways involving manipulating strings, >> paste(), etc.; but I'm sure it must be possible more elegantly. > > You mean like interaction()?
Thanks! Yes, interaction(A,B,drop=TRUE) does it. Best wishes, Ted. -------------------------------------------------------------------- E-Mail: (Ted Harding) <[EMAIL PROTECTED]> Fax-to-email: +44 (0)870 167 1972 Date: 15-Jun-04 Time: 09:54:18 ------------------------------ XFMail ------------------------------ ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
