> Args <- paste(c("female", "male"), "= names", 1:2, sep="")
> Args
[1] "female= names1" "male= names2" > listText <- paste("names.list<-list(",
+ paste(Args, collapse=","), ")")
> listText
[1] "names.list<-list( female= names1,male= names2 )"
> names1 <- c("Sue", "Betty")
> names2 <- c("Bill", "Sam")
> eval(parse(text=listText))
> names.list
$female
[1] "Sue" "Betty"
$male [1] "Bill" "Sam"
hope this helps. spencer graves
p.s. "str" is the name of a function to "Compactly Display the Structure of an Arbitrary R Object". I prefer to avoid masking functions with local objects, even though R can tell which object is desired in many but not all contexts. To avoid this, I often test a name before I use it. When I don't get, "Object ... not found", I try something different, e.g., using capital letters somewhere or adding a "." at the end. This also has the advantage of introducing me or reminding me of functions I may not have known.
Robin Gruna wrote:
Hi,
let's see, if someone can help my with this one:
I have the string as follows:
str<-("one","two","three")
Now I want to concatenate the items to one string, seperateted by space or
something else,
str
"one, two, three"
If possible without a loop.
My actual goal ist to create string like
str.namesand pass it as argument to list(), intending to create a list
"female = names1, male = names2"
names.list<-list( female = names1, male = names2)
Thanks a lot, Robin
______________________________________________
[EMAIL PROTECTED] mailing list
https://www.stat.math.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
