Hi Paul,
I think lattice's histogram will do what you want, and in a friendlier
manner. Take a look at this example:
require(lattice)
a <- data.frame(draw = as.vector(mapply(rnorm, rep(100, 4), rep(0, 4),
1:4)),
sd = factor(paste("sd =", rep(1:4, each = 100))))
Go ahead and examine "a": "draw" contains the aggregate results of random
draws with four different standard deviations, while "sd" tells you which
value of the standard deviation generated the draw. Naturally, I'd want four
histograms as my result. With lattice, I'd do
histogram(~ draw | sd, a)
and get back a sensible result.
Was this what you were looking for?
Kevin
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Schwarz,Paul
Sent: Wednesday, September 01, 2004 11:45 AM
To: [EMAIL PROTECTED]
Subject: [R] using hist() with tapply()
Hi,
I've been passing the hist() function to tapply() to quickly generate
histograms based on the list of factors supplied to tapply(). However, I
have not figured out how to generate titles for each of the histograms,
which paste in the unique values of the list factors as part of the
histogram title. I'm hoping that someone can tell me how to do this.
Thanks for your time and consideration,
-Paul Schwarz
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