<see below>
Erin Hodgess wrote:
Dear R and S People:
First, thank you to so many people for your help to my problem.
Here is the solution:
a <- 0.5*(outer(1:n3,1:n3,function(x,y,n2.){n2. - pmax(x,y)},n2.=n2))
I have one final pesky question, please: During my experiments, I tried the following:
a <- 0.5*(outer(1:n3,1:n3,function(x,y,n2.=n2){n2. - pmax(x,y)}))
In S-Plus, the function "outer" can't find "n2". In the form
outer(1:n3,1:n3,function(x,y,n2.=n2){n2. - pmax(x,y)}), n2.=n2)the value of "n2" is passed to "n2." as part of the "..." argument. Someone else mentioned Venables and Ripley (2000) S Programming (Springer). Please see this or some other discussion of the "..." argument.
hope this helps. spencer graves
Why doesn't this work please?
thank you!
Sincerely, Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: [EMAIL PROTECTED] -------------------------------------------------------------------- This message was distributed by [EMAIL PROTECTED] To ...(s-news.. clipped)...
-- Spencer Graves, PhD, Senior Development Engineer O: (408)938-4420; mobile: (408)655-4567
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