> From: Paul Roebuck
>
> On Wed, 15 Sep 2004, Peter Dalgaard wrote:
>
> > Paul Roebuck <[EMAIL PROTECTED]> writes:
> >
> > > Is there a means to split a vector into its individual
> > > elements without going the brute-force route for arguments
> > > to a predefined function call?
> > >
> > > offred.rgb <- c(1, 0, 0) * 0.60;
> > >
> > > ## Brute force style
> > > offred.col <- rgb(offred.rgb[1],
> > > offred.rgb[2],
> > > offred.rgb[3],
> > > names = "offred")
> > > ## Desired style
> > > offred.col <- rgb(silver.bullet(offred.rgb),
> > > names = "offred")
> >
> > The closest is probably this:
> >
> > offred.col <- do.call("rgb", c(as.list(offred.rgb),
> > list(names="offred")))
>
> Everyone offered 'do.call' as the solution. While that
> works, is it to say that there is no means of expanding
> the expression as an argument to the original function?
What would be the point? That's what do.call() does for you internally.
Andy
> > (ever read/seen The Handmaid's Tale, btw?)
> >
>
> Not yet. Though renaming my sample variable 'off.red.col'
> would avoid future confusion with oppressed handmaids.
>
> ----------------------------------------------------------
> SIGSIG -- signature too long (core dumped)
>
> ______________________________________________
> [EMAIL PROTECTED] mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide!
> http://www.R-project.org/posting-guide.html
>
>
______________________________________________
[EMAIL PROTECTED] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
