You want as.Date, not strptime that gives you a *list*.
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On Mon, 8 Nov 2004, Jo�o Mendes Moreira wrote:
> Hello,
>
> I have the following problem:
> test is a data frame with 9 fields. The field test$Date is factorized with
> dates. The format is dd-mm-yyyy (using Oracle notation). I want to convert
> this to Date in '%Y-%m-%d format.
> What I am doing is:
> for (i in 1:nrow(test))
> {
> test[i,]$Data<-strptime(substring(test[i,]$Data,1,10),"%d-%m-%Y")
> }
>
> test is a data frame.
>
> The error is:
> Error in "$<-.data.frame"(`*tmp*`, "Data", value = list(sec = 0, min = 0, :
> replacement has 9 rows, data has 1
>
> But if I do:
> strptime(substring(test[1:nrow(teste),]$Data,1,10),"%d-%m-%Y")
> it works! Why the assignement does not work?
--
Brian D. Ripley, [EMAIL PROTECTED]
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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