a=c(1,1,1,1,1) # generate the first list b=c(2,2,2) # generate a second list d=list(a,b) # make a list of a and b ( e=c(d,a) ) [[1]] [1] 1 1 1 1 1
[[2]] [1] 2 2 2
[[3]] [1] 1
[[4]] [1] 1
[[5]] [1] 1
[[6]] [1] 1
[[7]] [1] 1
If no, have you read sec. 6 in "An Introduction to R" [the first option available from help.start()]?
In this example, note that e[1] is a list with only one attributes, namely the vector 1 1 1 1 1; e[[1]] is not a list but that vector itself.
hope this helps. spencer graves
Karla Sartor wrote:
Hello all,
As a general programming question I can't seem to figure out how to make a list of lists in R.
As matrices won't work as they have to be rectangular.
I am sure that there is an easy solution but...
the specific situation is this:
- I have created a Tukey confidence interval table and have listed the means that are not significantly different
- then using these not significantly different pairs I have created the groups of means that are not significantly different from each other
the issue then is that many of these lists are subsets of other lists and I need to check for this.
Below is a little program is illustrate the issue
> a=c(1,1,1,1,1) # generate the first list
> b=c(2,2,2) # generate a second list
> c=c(a,b) #combine them
> cat(c, "\n") # and print
1 1 1 1 1 2 2 2 # this is 1-D!!! ahh
> d=list(a,b) # make a list of a and b
> d # and print
[[1]] #this is exactly what I want, but continue
[1] 1 1 1 1 1
[[2]] [1] 2 2 2
> e=list(d,a) # now on the next iteration I need to add another list to this list of lists
> e # and print
[[1]] # ahh all hell has broken loose and this is not what I want
[[1]][[1]] # desired result below
[1] 1 1 1 1 1
[[1]][[2]] [1] 2 2 2
[[2]] [1] 1 1 1 1 1
------------- desired result
#wrong code but this is what I want to happen a=c(1,1,1,1,1,1,1) for(i in 1:5) { a=list(a,1:5) }
output I want is (something like) [1] 1 1 1 1 1 1 1 [2] 1 2 3 4 5 [3] 1 2 3 4 5 [4] 1 2 3 4 5 [5] 1 2 3 4 5 [6] 1 2 3 4 5
so then I could call cat(a[1]) and get 1 1 1 1 1 1 1 1 and cat(a[2]) and get 1 2 3 4 5
Anyone know the answer (hopefully simple)
Cheers,
Karla Sartor
---------------------------------------------------------- Karla Sartor Montana State University - LRES [EMAIL PROTECTED]
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