On Wed, 24 Nov 2004 14:38:19 -0500, "Heather J. Branton" <[EMAIL PROTECTED]>
wrote :

>Thank you so much for each of your responses. But to make sure I am 
>clear (in my own mind), is this correct?
>
>If  x = 2^y
>Then  y = log2(x)

Yes, that's right.

Duncan Murdoch

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