"Dimitris Rizopoulos" <[EMAIL PROTECTED]> writes: > Hi Alexander, > > you could try: > > my.string <- "A==1 & B==2" > (my.frame <- data.frame(A=sample(1:2, 20, TRUE), B=sample(1:2, 20, > TRUE))) > subset(my.frame, eval(parse(text=my.string)))
Hmm, considering the nonstandard evaluation that is going on inside subset(), I think I'd rather try my.frame <- data.frame(A=sample(1:2, 20, TRUE), B=sample(1:2, 20,TRUE)) my.string <- "A==1 & B==2" l <- as.list(parse(text=my.string)) names(l)<-"sub" eval(substitute(subset(my.frame, sub), l)) A B 18 1 2 (or perhaps l <- list(sub=parse(text=my.string)[[1]]) is less cryptic). Point being that this way you'll literally evaluate > substitute(subset(my.frame, sub), l) subset(my.frame, A == 1 & B == 2) -- O__ ---- Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907 ______________________________________________ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
