Is this an impossible task?
How about just problem 2 below, having one pch in one legend entry, but no pch in the second?
Please be at least a little bit patient! This is not a hotline! People are not working 24 hours a day just to answer your questions at once - they are answering questions on a voluntary basis!
answer 1) is not straightforward, but you might want to use one of fillable symbols mentioned in ?points, e.g. number 21
answer 2) pch = c(1, NA) should do the trick.
legend(....., pch=c(21,NA), lwd=c(1,3), lty=c(1,3), pt.bg="white", col=1:2)
Uwe Ligges
On Thu, 25 Nov 2004, Dan Bolser wrote:
Hello,
I am using code like the following to create as simple plot...
plot(x,y,type='b') lines(lowess(x,y),lwd=3,lty=3,col=2)
I want to add a legend which shows lines looking exactly like those used in my plot, i.e. a thin black line with gaps taken up by circles (the default for type='b', and a thick dashed red line with no pch at all).
I have two problems,
1) making the pch on the first like look like type = 'b' (gaps around pch) 2) surpressing a pch on for the second line
Any help with these two problems would be greatly appreciated.
Any archive of plots and code to browse which could help me visually find what I want and then copy the code?
An online user contributable database of 'graphics in R' would be smashing.
How come some smart people dont just let me do something like
legend(xpos,ypos,legend=add)
to add a legend to the current plot for all the relevant points and lines which have been added so far?
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