bogdan romocea wrote:
Here's something that works. I'm sure there are better solutions (in
particular the paste part - I couldn't figure out how to avoid typing
a[i,1], ..., a[i,10]).
a <- matrix(nrow=1000,ncol=10)
for (i in 1:1000)
for (j in 1:10)
a[i,j] <- sample(1:0,1)
b <- vector(mode="character")
for (i in 1:1000)
b[i] <- paste(a[i,1],a[i,2],a[i,3],a[i,4],a[i,5],
a[i,6],a[i,7],a[i,8],a[i,9],a[i,10],sep="")
Or
b <- apply(a, 1, function(x) paste(x, sep="", collapse=""))
Kjetil
#the most frequent row
table(b)[table(b) == max(table(b))]
HTH,
b.
-----Original Message-----
From: Lisa Pappas [mailto:[EMAIL PROTECTED]
Sent: Thursday, December 09, 2004 5:15 PM
To: [EMAIL PROTECTED]
Subject: [R] finding the most frequent row
I am bootstrapping using a function that I have defined. The
"Statistic" of the function is an array of 10 numbers. Therefore if
I use 1000 replications, the "t" matrix will have 1000 rows each of
which is a bootstrap replicate of this 10 number array (10 columns).
Is there any easy way in R to determine which row appears the most
frequently?
Thanks,
Lisa Pappas
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--
Kjetil Halvorsen.
Peace is the most effective weapon of mass construction.
-- Mahdi Elmandjra
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