Dear Thomas,
My suggestion would be as follows:
y <- rnorm(3000) dim(y) <- c(3, 1000).
#then create three column vectors out of y using cbind():
w<-cbind(y[1,],y[2,],y[3,])
# and calculate the row means
for (i in 1:1000) z[i]<-mean(w[i,1:3])
z
Hope I got it right!
Regards, Christoph
Thomas Hopper wrote:
Hello,
I've got an array defined as y <- rnorm(3000), dim(y) <- c(3, 1000).
I'd like to produce a 1000-element vector z that is the mean of the corresponding elements of y (like z[1,1] <- mean(y[1,1], y[2,1], y[3,1])), but being new to R, I'm not sure how to do this for all elements at once (or, at least, simply). Any help is appreciated.
Thanks,
Tom
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