Hi Mick,
try the following:
dat[] <- lapply(dat, function(x) ifelse(is.na(x), 0, x)) dat
I hope it helps.
Best, Dimitris
---- Dimitris Rizopoulos Ph.D. Student Biostatistical Centre School of Public Health Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium Tel: +32/16/336899 Fax: +32/16/337015 Web: http://www.med.kuleuven.ac.be/biostat http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm
----- Original Message ----- From: "michael watson (IAH-C)" <[EMAIL PROTECTED]>
To: <r-help@stat.math.ethz.ch>
Sent: Friday, January 14, 2005 12:20 PM
Subject: [R] Replacing NAs in a data frame using is.na() fails if there areno NAs
Hi
This is a difference between the way matrices and data frames work I
guess. I want to replace the NA values in a data frame by 0, and the
code works as long as the data frame in question actually includes an NA
value. If it doesn't, there is an error:
df <- data.frame(c1=c(1,1,1),c2=c(2,2,NA)) df[is.na(df)] <- 0 df
df <- data.frame(c1=c(1,1,1),c2=c(2,2,2)) df[is.na(df)] <- 0 Df
Any help would be appreciated. I could just convert the data frame to a
matrix, execute the code, then convert it back to a data frame, but that
appears long winded.
Thanks Mick
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