How about "data.lm$model" ?
On Wed, 2005-02-09 at 16:32 +0100, [EMAIL PROTECTED] wrote: > Petr, > > It works perfectly! But I still have a question; > > I have fit the following data; > > x,y,z > 1,10,11 > 2,11,15 > 3,12,21 > 4,13,29 > 5,14,39 > 6,15,51 > 7,16,65 > 8,17,81 > 9,18,99 > 10,19,119 > > >dat.lm <- lm(z~I(x^2)+y, data=dat) > >dat.lm > > Call: > lm(formula = z ~ I(x^2) + y, data = dat) > > Coefficients: > (Intercept) I(x^2) y > 1.841e-14 1.000e+00 1.000e+00 > > How do I create the "z" matrix from dat.lm?? Without having to type over > all the coefficients? > > Kind regards, Darius Blaszijk > > ------------------------- Oorspronkelijk bericht ------------------------- > Onderwerp: Re: Fw: [R] Contour plot > Van: "Petr Pikal" <[EMAIL PROTECTED]> > Datum: Wo, 9 februari, 2005 11:23 am > Aan: [EMAIL PROTECTED] > r-help@stat.math.ethz.ch > -------------------------------------------------------------------------- > > Hi Darius > > > On 8 Feb 2005 at 17:43, [EMAIL PROTECTED] wrote: > > > I understand that I need to have a (in this case) square matrix with all > the data. But the question now is; > > > > - can the contourplot not interpolate the missing values > > > > or alternatively > > > > - I have fit a model to the z data (z = 100 + 0.5x + 0.5y). How can I > make from this model a "square" matrix z to make a contour plot? > > > Will > > x<-1:10 > y<-1:10 > z <- outer(x,y,function(x,y) 100 + 0.5*x + 0.5*y) > contour(x,y,z) > > work as you wish? > Cheers > Petr > > > > > > Kind regards, Darius Blaszijk > > > > ----- Original Message ----- > > From: "Achim Zeileis" <[EMAIL PROTECTED]> > > To: <[EMAIL PROTECTED]> > > Cc: <r-help@stat.math.ethz.ch> > > Sent: Tuesday, February 08, 2005 1:51 AM > > Subject: Re: [R] Contour plot > > > > > > > On Tue, 8 Feb 2005 01:15:06 +0100 [EMAIL PROTECTED] wrote: > > > > > > > Hello, > > > > > > > > I would like to make a contourplot of the following data; > > > > > > > > > x <- 1:10 > > > > > y <- 1:10 > > > > > z <- 100:110 > > > > > > > > By doing >contour(x,y,z) I get the following error; > > > > > > > > "Error in contour.default(x, y, z) : no proper `z' matrix > > > > specified" > > > > > > > > How do I fix this?? > > > > > > x and y specify a grid and thus z must provide a value for each > combination of the x's and y's! For example: > > > x <- y <- 1:10 > > > contour(x, y, outer(x, y)) > > > Also look at > > > outer(x, y) > > > and read ?contour. > > > > > > Z > > > > > > > Kind regards, Datius Blaszijk > > > > > > > > [[alternative HTML version deleted]] > > > > > > > > ______________________________________________ > > > > R-help@stat.math.ethz.ch mailing list > > > > https://stat.ethz.ch/mailman/listinfo/r-help > > > > PLEASE do read the posting guide! > > > > http://www.R-project.org/posting-guide.html > > > > > > > > ______________________________________________ > > R-help@stat.math.ethz.ch mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide! > > http://www.R-project.org/posting-guide.html > > Petr Pikal > [EMAIL PROTECTED] > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html