Dear Marcelo, This is, I guess, permn() in the combinat package.
How about unique(matrix(unlist(permn(c(1,1,0))), ncol=3, byrow=TRUE)), which leaves the permutations in the rows of a matrix? I hope this helps, John -------------------------------- John Fox Department of Sociology McMaster University Hamilton, Ontario Canada L8S 4M4 905-525-9140x23604 http://socserv.mcmaster.ca/jfox -------------------------------- > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of > [EMAIL PROTECTED] > Sent: Sunday, February 13, 2005 9:45 AM > To: [email protected] > Subject: [R] combinations without repetition > > The solution is probably simple but I need someone to point me to it. > How can I reduce the following 6 permutations to the 3 unique > combinations > (1,1,0) (1,0,1) (0,1,1)? > > permn(c(1,1,0)) > [[1]] > [1] 1 1 0 > > [[2]] > [1] 1 0 1 > > [[3]] > [1] 0 1 1 > > [[4]] > [1] 0 1 1 > > [[5]] > [1] 1 0 1 > > [[6]] > [1] 1 1 0 > > Thanks a lot > Marcelo Jenny > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! > http://www.R-project.org/posting-guide.html ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
