I think that this is an easy one...
I have a matrix where each row is an (x,y,z) triplet. Given a potential (xnew,ynew,znew) triplet I want to know if the matrix already contains a row with the new values (the space already has that point). I can do it using a for loop, but I would like to know if there is anyway in which I can do it without the for loop.
I do it now like this (this algorithm appears to be correct, but there are probably much cleaner ways to write it.)
has.row <- function(m, r) {
for (i in 1:length(y[,1])) {
x <- ifelse(y[i,1:3] == r, 1, 0)
if (sum(x) == 3) {
return(TRUE)
}
}
return(FALSE)
}Thanks, jim
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